4.9t^2-2t-6=0

Solution for 4.9t^2-2t-6=0 equation:

4.9t^2-2t-6=0

a = 4.9; b = -2; c = -6;
Δ = b2-4ac
Δ = -22-4·4.9·(-6)
Δ = 121.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{121.6}}{2*4.9}=\frac{2-\sqrt{121.6}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{121.6}}{2*4.9}=\frac{2+\sqrt{121.6}}{9.8}
$